common subsequence造句
例句與造句
- The first part of the present paper is preliminaries . at the second part we show a lemma as follows : supposing s1 , s2 , . . . are strictly increasing sequences , then there exists a strictly increasing sequence t such that for any i , si and t contain a common subsequence having upper density 1 in t . using the lemma we give a chaotic form more rigorous than distribution chaos in a sequence
本文第一部分介紹有關(guān)的預(yù)備知識(shí);第二部分首先證明了一個(gè)關(guān)鍵性引理:對(duì)于給定的可數(shù)(包括有限)個(gè)嚴(yán)格遞增的正整數(shù)序列s _ 1 , s _ 2 , … ,可以找到某一個(gè)嚴(yán)格遞增的正整數(shù)序列t ,使得對(duì)于每一個(gè)i = 1 , 2 , … ,序列s _ i與序列t有一個(gè)共同的子序列,它在序列t中的上密度為1 。 - Finally , the ability of applying the approved aco algorithm to msa is studied . the idea of divide - and - conquer is adopted to improving the progressive algorithm and the longest common subsequence of multiple sequences is proposed as the partition points of multiple sequences . also , the paper presents how to solve the longest common subsequence of multiple sequences by the approved aco algorithm for mcp
最后,本文對(duì)改進(jìn)的蟻群優(yōu)化算法在多序列比對(duì)問題上的應(yīng)用進(jìn)行了研究,采取分治思想改進(jìn)現(xiàn)有的progressive算法,提出利用最長(zhǎng)公共子序列進(jìn)行多序列分割的策略,并給出怎樣利用解決最大團(tuán)問題的蟻群優(yōu)化算法求解多序列的最長(zhǎng)公共子序列的方法。 - It's difficult to find common subsequence in a sentence. 用common subsequence造句挺難的